What sizes of gage pins are needed for a dimension of 9/32 + or - 1/64 inches?

For a dimension of 9/32 inches with a tolerance of ±1/64 inches, you first convert the fraction to a decimal. The fraction 9/32 equals 0.28125 inches. The tolerance of ±1/64 inches is approximately ±0.015625 inches, which means you add and subtract this tolerance to the base dimension to find the acceptable range.

Calculating the minimum and maximum dimensions gives:

• Minimum: 0.28125 - 0.015625 = 0.265625 inches

• Maximum: 0.28125 + 0.015625 = 0.296875 inches

When looking for the appropriate gage pins, you need sizes that fall within this range of 0.265625 to 0.296875 inches. The chosen sizes from the correct answer, 0.297 inches and 0.266 inches, both fit snugly within this range.

This alignment with the given dimension and tolerance validates the selection, as gage pins are utilized to check whether a part conforms to specified dimensions. The sizes need to ensure accurate measurement and compatibility, which the selected pins do. The other options do not maintain the necessary sizes or fall outside the acceptable range,